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7m^2-14m-105=0
a = 7; b = -14; c = -105;
Δ = b2-4ac
Δ = -142-4·7·(-105)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-56}{2*7}=\frac{-42}{14} =-3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+56}{2*7}=\frac{70}{14} =5 $
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